# Science

posted by Abby

The following reaction:

2SO3 (g) ! 2SO2 (g) + O2 (g) has an equilibrium constant equal to 0.23 M. If the following concentrations are present:

[SO2] =0.480 M, [O2] = 0.561 M, [SO3] = 0.220 M, is the reaction at equilibrium? If not, which way must it shift to reach equilibrium?

1. PsyDAG

More specific labeling of the subject would be more likely to attract tutors with expertise in this area.

2. DrBob222

Find the reaction quotient or Q.
Q = (SO2)^2 x (O2)/(SO3)^2
Q = (0.480)^2(0.561)/(0.220)^2
Q = 2.67
Compare this to K = 0.23 in the problem.
Q is to high meaning SO2 and O2 are too high and SO3 is too low; therefore, it much shift to the left to reach equilibrium. That way SO2 and O2 are lowered and SO3 is raised.

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