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A large fish hangs from a spring balance supported from the roof of an elevator.

If the elevator has an upward acceleration of 2.85m/s^2 and the balance reads 60.0N , what is the true weight of the fish?
Under what circumstances will the balance read 39.0N ?

  • physics -

    True Weight of fish:

    F= ma + mg

    a=2.85 m/s^s
    g=9.80 m/s^2

    Plug into formula where you are solving for m:

    F = ma + mg

    60.0 N = (2.85)m + (9.80)m
    60.0 N = (12.65)m
    m= 60.0N/12.65
    m= 4.74 kg => 4740 g => 46.5 N

    Under what circumstances will the balance read 39.0 N?

    Formula: ∑F = F(normal) + F(weight)

    ∑F= a(4.74kg)
    F(normal)= 39.0 N

    Plug into formula:

    ∑F = F(normal) + F(weight)
    a(4.74) = 39.0 N + (-9.80)(4.74)
    a(4.74) = -7.452
    a = -1.57 m/s^2

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