posted by amanda .
A basketball player has a 40% shooting average from the free-throw line. If she takes two free throws, estimate the probability that she will make both of them. Use the following list of digits which was taken from a table of random numbers. Let the digits 0-3 represent a made free throw and let the digits 4-9 represent a miss. Start at the top left of the table and move all the way across to the right of the table before moving down to the next row.
52052 24004 03845 11507
27510 33761 86563 61729
48061 59412 79969 11339
27324 72723 22406 86253
29970 95877 70975 99120
The probability of making two in a row is (2/5)^2 = 4/25.
I have no idea what the (A) - (D) part of your question is all about.
You could use the numerical entries to compute the actual fraction of free throws made, and the fraction of consecutive pairs of free throws made.
45 of 100 free throws were made (45%), which is better then the supposed average.
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