# Pre-Calc

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How would I solve:

X^(4/3)+X^(2/3)=28

• Pre-Calc -

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• Pre-Calc -

let x^(2/3) = y
then we have
y^2 + y - 28 = 0
y = (-1 ± √113)/2

so x^(2/3) = (1+√113)/2
x = [(1 + √113)/2]^(3/2) = appr. 10.566

or x^(2/3) = (-1 - √113)/2 , which has no solution

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