physics
posted by Gay Lyn .
A car and a coach leave from the same place, at the same time, traveling to the same destination. The destination is 140 miles away. The car travels 40 MPH, and the coach travels 30 MPH. The car arrives at the destination at noon.
What time does the coach arrive?

Vavg = X/T so T = X/Vavg
Car: 140 miles/40 mph = 3.5 hours
Coach: 140 miles/30 mph = 4.66 hours
So the coach arrive 1.66 hours after the car.
.66 *60 = 40 minutes so:
The coach arrives at 1:40 pm