1. If a 500N person is skiing on a slope with an angle of incline of 67 degrees and there was a friction coefficient of 0.19, determine the person’s acceleration rate. If starting from rest, what is the overall displacement after 30 seconds?
acceleration rate a = Fnet/M
M = 500/g = 51.0 kg
Fnet = (weight component down slope) - (friction)
= W sin67 - W cos67*0.19
= 460 - 37 = 423 N
Now you can calculate a.
The displacement in time t is (1/2)at^2.
It is highly unlikely this high acceleration rate (a) could be maintained for 30 seconds. Aerodynamic friction will become important after about 5 seconds.