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posted by RANDA .
Given the quadratic function f(x) = x2 – 12x + 36, find a value of x such that f(x) = 25.

Given f(x) = x2 – 12x + 36
and f(x)=25, equate:
25 = x²  12x + 36
x²12x+11=0
(x11)(x1)=0
therefore x=11 or x=1
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