physics
posted by dd
1. The best leaper in the animal kingdom is the puma, which can jump to a height of 12 ft when leaving the ground at an angle of 45°. With what speed, in SI units, must the animal leave the ground to reach that height?

drwls
(Vo sin45)^2 = 2 g H
Vo^2 = 4 g H
Vo = 2 sqrt(g H)
g = 32.2 ft/s^2
Vo = 78.4 ft/s = 53.5 mph 
S.C.Benjamin
0 = (Vcos45)^2 + 2 (32) 12
v^2 (1/2) = 768
v^2 = 1536
v = 39.2 ft/s
v = 12 m/s 
drwls
SCB is correct. I made a mistake calculating Vo.
Vo = 39.3 m/s
sin and cos 45 are the same, but in general the sine of the angle from horizontal should be used. 
Anonymous
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