Algebra-exponent

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Please help me solve this!!!!
4*(3-x)^4/3 - 5 = 59
(4/3 is an exponent)
I got to this far... (3-x)^4/3 = 16
But how do I get rid of the exponent? Please help me my final is tomorrow and I still don't know :(

  • Algebra-exponent -

    (3-x)^4/3 = 16 , great so far
    raise both sides to the 3/4
    [(3-x)^4/3]^(3/4) = 16^(3/4)
    3-x = 8
    x = -5

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