pre calculous
posted by kelly .
solve each equation algebraically and check it by substituing into the orignall equation.
50e^0.035x=200
3LN(x3)+4=5
Method of your choice by solving.
logx^2=6
Logx^4=2
2x2^x/2=4
e^x+e^x/2=4
500/1+25e^.3x=200

50e^(0.035x)=200
e^(.035x) = 4
take ln of both sides
ln(e^(.035x)) = ln4
.035x lne = ln4, but lne = 1
x = ln4 / .035 = appr. 39.6
log x^2 = 6
by definition:
x^2 = 10^6
x = 10^3 = 1000
do logx^4 = 2 the same way
2x2^x/2=4 : I have a feeling that is not what you meant, without brackets I cannot tell what the equation is. I think the first term is probably 2^x
e^x+e^x/2=4
Again, I think you meant:
e^x+e^(x/2) = 4
let e^(x/2) = y , where y is a positive real number
then e^(x/2) = 1/y
and e^x = 1/y^2
so 1/y2 + y = 4
1 + y^3 = 4y^2
y^3  4y^2 + 1 = 0
I used a program to find
y = .54 or y = 3.94 appr. , there is also a negative root which would not be allowed
so e^(x/2) = .54 or ..... use the other root
x/2 = ln.54
x = 1.2324 or ......
last question, way too ambiguous without brackets.
Respond to this Question
Similar Questions

PreCalculus
The Richtr scale was evied y Cahrles F.Richter a American geologist. The scale is based on the equation M(x)=logx/x0(little 0), where x is the seismographic reading of the earthquake and x0 i 1 miron 0.001mm (the seismographic reading … 
Math
these are some problems i do not get any help is appreciated. These are copied exactly from the worksheet so i don't think i wrote anything wrong. Please explain it for me and could i get the answer thanks (: Log7 x= ½ log7 36 (log … 
algebra
If LOGx (A)=0.7 and LOGx (B) =0.5 how do I solve LOGx (B/A) 
math
I tried everthing but,I couldn't solve it. Please help me.the answer at the back is 40960.13 question: solve for x and check your solution. logx/log2 + logx/log4 + logx/log8 + logx/log16 = 25 THANK YOU FOR YOUR KIND HELP!!!! 
Calculus
Find f'(x) if f(x)= Logx(x^25x+6) NOTE: that logx is a sub x 
^Maths^
If Logx6 base3=2y and Logx7 base2=3y, show that x^213x+42=72y 
logarithms maths
logx+logx+nlogx/n.plz solve with explanation thanks 
Precal
Solve the equation: Logx=1log(x3) 
math algebra
Sum the following term of progression to the last term, logx, logx^2 logx^3.... logx^120 
value
show that the sum of nterm of the progression is logx,logx^2,logx^3,logx^4is n(n+1)/2 logx