physics
posted by ashley .
Two ants race across a table 70 cm long. One travels at 5.7 cm/s and the other at 3.99999 cm/s. When the first one crosses the finish line,how far behind is the second one? Answer in units of cm

Are we to assume that they started at the same time?
3.9999 cm/s might as well be called 4.0 cm/s, since there are only two significant figures for other numbers. 
t1 = 70cm / 5.7cm/s = 12.88s = the 1st
ants' time.
d2=4cm/s * 12.88s = 49.12cm = Distance the 2nd ant ran during the 12.88s.
d = 70  49.12 = 20.88cm = Distance behind.
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