trig
posted by jacara .
FInd the exact value pf the 6 trig function of alpha
Given: point (2,6) on the terminal side of the angle in standard position
sin alpha
cos alpha
tan alpha
sec alpha
csc alpha
cot alpha

(0,0), (2,6).
X = 20 = 2.
Y = 60 = 6.
r = sqrt((2)^2+(6)^2) = sqrt40 =
sqrt(4*10) = 2sqrt10.
sinA = Y/r = 6/2sqrt10 = 3/sqrt10 =
3sqrt10/10.
cosA = X/r = 2 / 2sqrt10 =
1 / sqrt10 = sqrt10 / 10.
tanA = Y/X = 6/2 = 3.
cscA = 1/sinA = 10 / 3sqrt10 =
10sqrt10 / 3*10 = 10sqrt10 / 30 =
sqrt10 / 3.
secA = 1/cosA = 3 / sqrt10 =
3sqrt10 / 10.
cotA = 1/tanA = 1/3.
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