geometry
posted by D .
Given the quadrilateral ABCD with the following vertices A(4, 0), B(10, 0), C(10, 10), and D(0, 14), find its area.

After you sketch it, it is easy to see that you can split the area up into 2 triangle and a square, whose areas are 28, 20 and 100 , for a total of 148
or
list the coordinates in a column, repeating the first point
4 0
10 0
10 10
0 14
4 0
the area is (1/2)( sum of downproducts  sum of upproducts)
 (1/2)(0+100+140+0 (0+0+056)
= (1/2(240 + 56) = 148
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