Calculus AB
posted by JAE92 .
I had to integrate [(x^2+1)/(x^2x)]dx with partial fractions. My answer was 2ln abs(x1) ln abs(x)+C. But the answer on the answer sheet has an extra +x that I did not account for. Is that a typo or did I integrate incorrectly?

(x^2+1)/(x^2x)=(x^2x+x+1)/(x^2x)=
=1+(x+1)/(x^2x)=1+2/(x1)1/x