algebra
posted by Jaden .
perform the indicated operation and simplify:
3x+6 x^24
 divided by 
4x+12 x3

(3x+6)/(4x+12) / (x^2  4)/(x3)
first, to divide, we get the reciprocal of the divisor (or the second term/ term at the right) and the operation will be multiplication. reciprocal is just interchanging the numerator and denominator terms. thus,
(3x+6)/(4x+12) * (x3)/(x^2  4)
factoring out each term,
[3(x+2)]/[4(x+3)] * (x3)/[(x2)(x+2)]
we can cancel out x+2:
[3(x3)]/[4(x+3)(x2)] or
(3x  9)/(4x^2 + 4x  24)
hope this helps~ :)
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