When performing a titration, 23.65 mL of 1.25 M calcium carbonste was used to neutralize 9.68 mL of HCl. What is the concentration of the HCl solution?
(Create a balanced equation first)
carbonate*
2HCl + CaCO3 ==> CaCl2 + CO2 + H2O
moles CaCO3 = M x L = ??
Convert moles CaCO3 to moles HCl using the coefficients in the balanced equation.
now M HCl = moles HCl/L HCl.
To create a balanced equation for the reaction between calcium carbonate (CaCO3) and hydrochloric acid (HCl), we need to understand the components involved in the reaction.
The balanced equation for the reaction is:
CaCO3 + 2HCl -> CaCl2 + CO2 + H2O
Now let's find the moles of calcium carbonate and HCl involved in the reaction.
Moles of calcium carbonate (CaCO3):
To find the moles of CaCO3, we can use the formula:
Moles = Volume (in liters) x Concentration (in moles per liter)
Given:
Volume of CaCO3 = 23.65 mL = 0.02365 L
Concentration of CaCO3 = 1.25 M
Using the formula, we can calculate the moles of CaCO3:
Moles of CaCO3 = 0.02365 L x 1.25 M = 0.02956 moles
According to the balanced equation, 1 mole of CaCO3 reacts with 2 moles of HCl. Therefore, the moles of HCl can be calculated as follows:
Moles of HCl = (0.02956 moles of CaCO3) / 2 = 0.01478 moles of HCl
Now, to find the concentration of HCl, we need to know the volume of HCl used.
Given:
Volume of HCl = 9.68 mL = 0.00968 L
To calculate the concentration of HCl, we can use the formula:
Concentration = Moles / Volume
Concentration of HCl = 0.01478 moles / 0.00968 L = 1.528 molarity (M)
Therefore, the concentration of the HCl solution is 1.528 M.