Post a New Question

trig

posted by .

verifying a solution.

4cos^2 2x-2=0

  • trig -

    4cos^2 2x-2=0
    cos^2 (2x) = 1/2
    cos (2x) = ± 1/√2
    2x = 45° or 2x = 135° or 2x = 225° or 2x = 315°

    x = 22.5°, 67.5°, 112.5°, 157.5, ...

    the period of cos 2x is 180°, so adding 180° to any of the above answers will produce a new answer.
    So there is an infinite number of solutions.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question