maths
posted by janet .
Please can you help me with this question?
Choose the option which is a false statement:
A arctan(tan2/3pi))=1/3pi
B arccos(cos(3/4pi))=3/4pi
C sin(arcsin(1/2pi))=1/2pi
D arcsin(1/2squareroot3)=1/3pi
E arcsin(sin(3/4pi))=1/4pi
F arccos (1/2squareroot2)=1/4pi

maths 
MathMate
The righthandside of all the answers are in terms of π, typically for angles.
The lefthandsides all return angles (arccos, arctan...) except one.
We also note that 1≤sin(x)≤1
so it is impossible that sin(x)>1.
Can you find that case?
Respond to this Question
Similar Questions

math
1)Find the amplitude of y=6cos4theta A)3/2 B)6 C)4 D)pi/2 I chose B 2)Find the period of y=tan5theta A)10pi B)2pi/5 C)5pi D)pi/5 I chose D 3)Find the phase shift of y=sin(theta3pi/4). A)3pi/4 B)3pi/4 C)4pi/3 D)4pi/3 I chose A 4)Find … 
PreCalculuscheck answers
State the period and phase shift of the function y=4tan(1/2x + 3pi/8) a) 2pi, 3pi/4 b) pi, 3pi/8 c) 2pi, 3pi/8 d) pi, 3pi/8 Answer: d 2) What is the equation for the inverse of y=cos x+3: a) y=Arccos(x+3) b) y=Arccos x3 c) y=Arccos … 
math
Evaluate. 1. sin^1(1/2) 2. cos^1[(root 3)/2] 3. arctan[(root3)/3] 4. cos(arccos2/3) 5. arcsin(sin 2pi) 6. sin(arccos 1) I got these values as my answers: 1. pi/6 2. 5pi/6 3. pi/6 4. 2/3 5. 2pi 6. 0 Can someone please tell me if … 
Pre CalFix to the question below
Let P be the point on the unit circle U that corresponds to t. Find the coordinates of P and the exact values of the trigonometric functions of t, whenever possible. (If there is no solution, enter NO SOLUTION.) 4pi = ( , ) sin(4pi) … 
PreCal(Please check)
1) Find all the solutions of the equation in the interval (0,2pi). sin 2x = sqrt3/2 I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them. 2x = 4pi/6 + 2npi 2x = 5pi/3 + 2npi Now I know that I have … 
PreCal(Please check)
1) Find all the solutions of the equation in the interval (0,2pi). sin 2x = sqrt3/2 I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them. 2x = 4pi/6 + 2npi 2x = 5pi/3 + 2npi Now I know that I have … 
Math
An Arc of length 6 cm subtends a 80 degree angle in a circle. What is the radius of the circle? 
math
find the trigonometric form of 1212(square root)3i a. 24(cos2pi/3 + isin 2pi/3) b. 24(cos4pi/3 + isin 4pi/3) c. 12(cos 4pi/3 + isin 4pi/3) d. 12(cos12pi/3 + isin 2pi/3) e. 12(squareroot) 2 (cos4pi/3 + isin 4pi/3) 
Trig
Find all solutions of the equation in the interval [0,2pi) 2 cos^2 xcos x = 0 2cos^2 + cosx + 0 (x+1/2) (x+0/2) (2x+1) (x+0) 1/2,0 2Pi/3, 4pi/3, pi/2, 3pi/2 my teacher circled pi/2 and 3pi/2 What did I do wrong? 
Algebra 2
What values for theta(0 <= theta <= 2pi) satisfy the equation?