maths

posted by .

Please can you help me with this question?

Choose the option which is a false statement:

A arctan(tan2/3pi))=-1/3pi

B arccos(cos(3/4pi))=3/4pi

C sin(arcsin(-1/2pi))=-1/2pi

D arcsin(1/2squareroot3)=1/3pi

E arcsin(sin(3/4pi))=1/4pi

F arccos (1/2squareroot2)=1/4pi

  • maths -

    The right-hand-side of all the answers are in terms of π, typically for angles.

    The left-hand-sides all return angles (arccos, arctan...) except one.
    We also note that -1≤sin(x)≤1
    so it is impossible that sin(x)>1.

    Can you find that case?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. math

    1)Find the amplitude of y=6cos4theta A)3/2 B)6 C)4 D)pi/2 I chose B 2)Find the period of y=tan5theta A)10pi B)2pi/5 C)5pi D)pi/5 I chose D 3)Find the phase shift of y=sin(theta-3pi/4). A)3pi/4 B)-3pi/4 C)4pi/3 D)-4pi/3 I chose A 4)Find …
  2. Pre-Calculus-check answers

    State the period and phase shift of the function y=-4tan(1/2x + 3pi/8) a) 2pi, -3pi/4 b) pi, 3pi/8 c) 2pi, 3pi/8 d) pi, -3pi/8 Answer: d 2) What is the equation for the inverse of y=cos x+3: a) y=Arccos(x+3) b) y=Arccos x-3 c) y=Arccos …
  3. math

    Evaluate. 1. sin^-1(-1/2) 2. cos^-1[(-root 3)/2] 3. arctan[(root3)/3] 4. cos(arccos2/3) 5. arcsin(sin 2pi) 6. sin(arccos 1) I got these values as my answers: 1. -pi/6 2. 5pi/6 3. pi/6 4. 2/3 5. 2pi 6. 0 Can someone please tell me if …
  4. Pre Cal---Fix to the question below

    Let P be the point on the unit circle U that corresponds to t. Find the coordinates of P and the exact values of the trigonometric functions of t, whenever possible. (If there is no solution, enter NO SOLUTION.) 4pi = ( , ) sin(4pi) …
  5. Pre-Cal(Please check)

    1) Find all the solutions of the equation in the interval (0,2pi). sin 2x = -sqrt3/2 I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them. 2x = 4pi/6 + 2npi 2x = 5pi/3 + 2npi Now I know that I have …
  6. Pre-Cal(Please check)

    1) Find all the solutions of the equation in the interval (0,2pi). sin 2x = -sqrt3/2 I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them. 2x = 4pi/6 + 2npi 2x = 5pi/3 + 2npi Now I know that I have …
  7. Math

    An Arc of length 6 cm subtends a 80 degree angle in a circle. What is the radius of the circle?
  8. math

    find the trigonometric form of -12-12(square root)3i a. 24(cos2pi/3 + isin 2pi/3) b. 24(cos4pi/3 + isin 4pi/3) c. 12(cos 4pi/3 + isin 4pi/3) d. 12(cos12pi/3 + isin 2pi/3) e. 12(squareroot) 2 (cos4pi/3 + isin 4pi/3)
  9. Trig

    Find all solutions of the equation in the interval [0,2pi) 2 cos^2 x-cos x = 0 -2cos^2 + cosx + 0 (x+1/2) (x+0/2) (2x+1) (x+0) -1/2,0 2Pi/3, 4pi/3, pi/2, 3pi/2 my teacher circled pi/2 and 3pi/2 What did I do wrong?
  10. Algebra 2

    What values for theta(0 <= theta <= 2pi) satisfy the equation?

More Similar Questions