In a unit cell(cubic)atoms A,B & C are located at corners, face-centres and edge centres respectively. If atoms touching one of the rectangular plane of symmetry and one of the tetrad axis are removed then formula of the compound will be?
1)ABC2
2)AC2
3)AB3C3
4)Both 1)& 2)
To determine the formula of the compound, we need to first understand the arrangement of atoms in a unit cell and then apply the given conditions to find the correct formula.
In a cubic unit cell, there are atoms located at the corners, face-centers, and edge centers. Let's consider the arrangement of atoms in a cubic unit cell:
- Atoms located at the corners: These atoms are denoted as A.
- Atoms located at the face-centers: These atoms are denoted as B.
- Atoms located at the edge centers: These atoms are denoted as C.
Now let's apply the given conditions:
1. Atoms touching one of the rectangular plane of symmetry: The atoms located at the face-centers (B) are touching one rectangular plane of symmetry.
2. Atoms touching one of the tetrad axis: The atoms located at the edge centers (C) are touching one tetrad axis.
According to the conditions, we need to remove the atoms that fulfill both conditions. In this case, we have to remove the atoms B and C.
After removing atoms B and C, we are left with atom A. Therefore, the formula of the compound will be "A" or "A1".
Hence, the correct answer is 2) AC2.