Maths calculus
posted by Stephen .
A rectangular box has a square crosssection and the sum of its length and the perimeter of this crosssection is 2 m. If the length of the box is x m, show that its volume V m^3 is given by V = [x(2x)^2]/16.
Hence find the maximum volume of the box.

2/27m^3
x=2/3
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