what is the accetic acid solution when 30ml .15M NaOH have been added to 50ml .1M HOAc?
To determine the concentration of the acetic acid (HOAc) solution after adding sodium hydroxide (NaOH), we need to consider the reaction between the two compounds. In this case, NaOH reacts with HOAc in a 1:1 ratio, forming sodium acetate (NaOAc) and water (H2O) in the process. The balanced chemical equation for this reaction is as follows:
NaOH + HOAc (acetic acid) → NaOAc (sodium acetate) + H2O
Now, let's calculate the moles of NaOH and HOAc in the given volumes and concentrations.
Moles of NaOH = Volume (in liters) x Concentration
Moles of HOAc = Volume (in liters) x Concentration
Given that:
Volume of NaOH (V1) = 30 mL = 30/1000 = 0.030 L
Concentration of NaOH (C1) = 0.15 M
Volume of HOAc (V2) = 50 mL = 50/1000 = 0.050 L
Concentration of HOAc (C2) = 0.1 M
Moles of NaOH = V1 x C1 = 0.030 L x 0.15 M
Moles of HOAc = V2 x C2 = 0.050 L x 0.1 M
After the reaction, the NaOH will completely react with the HOAc. Since the reaction occurs in a 1:1 ratio, the amount of NaOH reacted will also be the amount of HOAc consumed.
To find the remaining amount (in moles) of HOAc, we subtract the moles of NaOH reacted from the initial moles of HOAc:
Remaining moles of HOAc = Initial moles of HOAc - Moles of NaOH
To find the concentration of acetic acid solution, we divide the remaining moles of HOAc by the total volume of the solution:
Concentration of acetic acid solution = Remaining moles of HOAc / Total volume of solution
Let's calculate the remaining moles of HOAc and the concentration of the acetic acid solution.
Moles of NaOH reacted = Moles of HOAc = 0.030 L x 0.15 M
Remaining moles of HOAc = Moles of HOAc - Moles of NaOH
Concentration of acetic acid solution = Remaining moles of HOAc / (V1 + V2)
By substituting the values into the equations and performing the calculations, the resulting concentration of the acetic acid solution can be determined.