algebra

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please shoe me how to factor this problem b^3-4b^2-9b+36

  • algebra -

    use "grouping"

    b^3-4b^2-9b+36
    = b^2(b-4) - 9(b-4)
    = (b-4)(b^2-9)
    = (b-4)(b+3)(b-3)

  • algebra -

    x3 + 2x2 + x + 2

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