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How long will it take a charged 80-ìF capacitor to lose 20 percent of its initial energy when it is allowed to discharge through a 45 ohm resistor?

  • Physics -

    i mean 80 microfarads

  • Physics -

    The time constant for charge decay is
    RC = 3.6*10^-3 s, if your ì symbol means "micro"

    For 80% of the initial energy, the charge must decrease to sqrt(0.8) = 89.4% of the initial value.

    exp(-t/RC) = 0.894
    t/RC = .1121
    t = 4*10^-4 seconds

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