Trig/PreCalc
posted by Eric .
Need help with current Trig problem for tomorrow:
Solve the logarithmic equation algebraically. Approximate the result to three decimal places.
6log3(0.5x)=11
I know to start off the equation you divide by 6.
I know the answer is 14.988. I just am puzzled on how to receive the answer.

6log3(0.5x)=11
log3 (.5x) = 11/6
3^[log3 (.5x)] = .5 x = 3^(11/6)
x = 2 * 3^(11/6)
x = 2 * 4.494
x = 14.9882972
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