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Monday, May 16, 2011 at 5:12pm
How do you solve csc2x + 1 = 0
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I need HELP Verify the identity Cot3X/CSCX=cosX(csc2X-1)
Verify the trigonometric identity: [(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I can't figure this out.
Verify the trigonometric identity: [(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I still can't figure this out.
solve for all real# sin2x(csc2x-2)=0
algebra 2 logs and trig
log(base 2)cotx - 2log(base 4)csc2x = log(base 2)cosx the answer should be x = pi/3, 5pi/3 not sure how to work it out though, any help?
PLEASEE HELPPMEEE!!!! cot2x+sec2x=tan2x+csc2x and 1+2sinxcosx/sinx+cosx=sinx + cosx
trig pre calc
cos x (sec x +cos x csc2x)=csc2x
Solve the trigonometric equations. 1.) SIN²x(CSC²x-1) 2.) COT x SEC X 3.) COS²[(π/2)-x]/COS X (Note: These mathematical problems are somewhat tricky, but useful for students as of learning how to their fundamental identities. …
Please solve it in step by step. integrate: ∫(cot2x-csc2x)^2 dx
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