Could anybody help me with these two problems, or at least the 1st one?
Thank you very much.
„« The measure of the third angle of a triangle is 38 degrees more than the second angle. The measure of the first angle is two less than twice the second angle, Find the measure of each angle.
„« Graph 5x + 2y = 6 and determine what are the x and y intercepts.
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okay so heres what i got for the first one.. Triangle has to equal 180 degrees
1st angle= 2x-2
2nd angle= x
3rd angle= x+38
add them all together and equal it to 180 degrees
in the end you would get
4x+36=180
solve for the equation and x is 36
now find the measure for each angle using 36
the second angle is 36
first angle and third angle? what do you think? :)
okay second onee..
5x + 2y = 6
need to make y alone on the left side..so bring everything over to the right
2y=-5x+6
divide by 2
y=-5/2x +3
put that into calculator or graph it by hand... your y intercept is already given to you which is 3
Hi Jess,
THank you. I got 36 as the angle for the 2nd, 1st 36x2-2, the third 36+8 which adds up to 180.
THe 2nd problem I got wacked out. I only get 1/2 of my graphing problems right.
Sure, I can help you with both of these problems.
1. Let's start with the first problem:
The first step is to assign variables to the angles in the triangle. Let's call the first angle x, the second angle y, and the third angle z.
According to the problem, we know that the measure of the third angle (z) is 38 degrees more than the second angle (y). So, we can write the equation: z = y + 38.
We also know that the measure of the first angle (x) is two less than twice the second angle (y). So, we can write the equation: x = 2y - 2.
Since we are dealing with angles in a triangle, we know that the sum of all three angles is equal to 180 degrees. Therefore, we can write the equation: x + y + z = 180.
Now we have three equations:
1. z = y + 38
2. x = 2y - 2
3. x + y + z = 180
To find the values of x, y, and z, we can solve these equations simultaneously. You can substitute the value of z from the first equation into the third equation, and substitute the value of x from the second equation into the third equation. This will give you a system of two equations in two variables (y and z).
Once you solve for y, you can substitute the value of y back into the second equation to find the value of x, and then substitute the values of x and y back into the first equation to find the value of z.
2. Moving on to the second problem:
To find the x and y intercepts of the equation 5x + 2y = 6, we need to find the points where the graph intersects the x-axis and the y-axis.
To find the x-intercept, we set y equal to 0 and solve for x. Substitute y = 0 into the equation:
5x + 2(0) = 6
5x = 6
x = 6/5
So, the x-intercept is (6/5, 0).
To find the y-intercept, we set x equal to 0 and solve for y. Substitute x = 0 into the equation:
5(0) + 2y = 6
2y = 6
y = 3
So, the y-intercept is (0, 3).
Now you know how to find the measure of each angle in the triangle and the x and y intercepts of the graph. Let me know if you have any other questions or need further clarification.