Applied Physics
posted by EJ .
An object is dropped from a height of 49 meters. The object takes 3.2s to hit the ground. The final velocity of the object when it hits the ground is 31 m/s

d = (1/2) g t^2
49 = (1/2)(9.8)t^2
t^2 = 10
t = 3.16 seconds
v = gt = 9.8*3.16 = 31 m/s
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