trig
posted by toshia .
simplify (sec^2x + csc^2x)  (tan^x +cot^2x) to either a constant or a basic trigonometric function.
Respond to this Question
Similar Questions

more trig.... how fun!!!!
if you can't help me with my first question hopw you can help me with this one. sec(x)/csc(x)=tan(x) thanx to anyone who can help From the definition of the sec and csc functions, and the tan function, sec(x)/csc(x) = sin(x)/cos(x) … 
Trig
Find the exact values of the six trigonometric functions 0 if the terminal side of 0 in standard position contains the points(5,4). (0 is not the number zero I don't know what its called) I have to find r first. r=sqrt x^2+y^2 r=sqrt … 
Pre Calculus.
Can someone check my answers please!!! Simplify (tan ^2 theta csc^2 theta1)/(tan^2 theta). My answer: 1 Simplify ((cos x)/(sec x1)) + ((cos x) /(sec x +1) My answer: 2cot^2 x Find a numerical value of one trigonometric function of … 
Math  Trig
I'm trying to verify these trigonometric identities. 1. 1 / [sec(x) * tan(x)] = csc(x)  sin(x) 2. csc(x)  sin(x) = cos(x) * cot(x) 3. 1/tan(x) + 1/cot(x) = tan(x) + cot(x) 4. csc(x)/sec(x) = cot(x) 
trig
simplify to a constant or basic trig function.. 1+tan(x)/1+cot(x) 
trig 26
simplify to a constant or trig func. 1. sec ²utan ²u/cos ²v+sin ²v change expression to only sines and cosines. then to a basic trig function. 2. sin(theta)  tan(theta)*cos(theta)+ cos(pi/2  theta) 3. (sec y  tan y)(sec y + … 
trigonometry repost
Reduce (csc^2 x  sec^2 X) to an expression containing only tan x. (is this correct? 
trig (precal class)
Suppose è is an acute angle of a right triangle. For this function, find the values of the remaining five trigonometric functions of è. Round to four decimal places. sin è = 0.1 cos è = tan è = cot è = csc è = sec è = 
Trig verifying identities
I am having trouble with this problem. sec^2(pi/2x)1= cot ^2x I got : By cofunction identity sec(90 degrees  x) = csc x secx csc1 = cot^2x Then split sec x and csc1 into two fractions and multiplied both numerator and denominators … 
Precalculus
Circle O below has radius 1. Eight segment lengths are labeled with lowercase letters. Six of these equal a trigonometric function of theta. Your answer to this problem should be a six letter sequence whose letters represent the segment …