Algebra 2
posted by Marie .
Identifying Conics. Put equation in standard form and graph.
9x^24y^290x+189=0

9(x^210x+2525)4y^2+189=0
9(x5)^22254y^2+189=0
9(x5)^24y^2=36
(x5)^2/2^2  y^2/3^2=1 hyperbola
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