geometry

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The distance between (-3,-1) and (3,y) is sq rt45.Find y?

  • geometry -

    √((3+3)^2 + (y+1)^2 ) = √45
    square both sides
    36 + (y+1)^2 = 45
    (y+1)^2 = 9
    y+1 = ± 3
    y = -1 ± 3
    = 2 or -4

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