Post a New Question


posted by .

4. Vinegar is a dilute solution of acetic acid. What is the concentration of acetic acid in the vinegar if 26.5 mL of NaOH at 0.250 M are required to neutralize 10.0 mL of vinegar?

  • chemistry -

    How many moles NaOH did you use? That is M x L = ??
    How many moles vinegar do you have in the 10 mL? Since the reaction is 1:1 (see equation below) the same number of moles of vinegar are in the 10 mL sample.
    Concn = M = moles/L. So that many moles in 0.010 L = ??
    CH3COOH + NaOH ==> CH3COONa + H2O

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question