Post a New Question


posted by .

A solution is prepared by dissolving 22.8 mL of methanol (d = 0.782 g/mL) in 100 mL of water (d = 1.00 g/mL) so that the final volume of solution is 118 mL. What is the percent methanol by mass?

  • Chem3 -

    22.8 mL methanol x 0.782 g/mL = grams methanol.
    mass soln = mass methanol + mass H2O
    %methanol w/w = (mass methanol/total mass soln)*100 = ??

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question