posted by Blaze
Supply the missing atomic symbol to complete the equation for the following nuclear fission reaction.
1/0n +235/92U ------> 137/52 Te +?/?X + 2 1/0 n + energy
also how do you decipher whether its 2 1/0n rather than 3?
The lower numbers must add to the same on both sides. The upper numbers must add to the same on both sides.
On the bottom. You have 92 + 0 on the left. There must be 92 on the right. We have 52 + 0 showing; the remainder must be the lower number for X. Look on the periodic table to find that element.
Top numbers are done the same way.
235+1 on the left = 236.
On the right, 236 - 137 -2 = top number for X.