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calculus

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let R be the region bounded by the x-axis, the graph of y=sqrt(x+1), and the line x=3.
Find the area of the region R

  • calculus -

    the curve starts at (-1,0)

    area = [integral] (x+1)^(1/2) dx from -1 to 3
    = (2/3)(x+1)^(3/2) from -1 to 3
    = (2/3)(4)^(3/2)
    = 16/3

    check my arithmetic

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