calculus
posted by paul .
let R be the region bounded by the xaxis, the graph of y=sqrt(x+1), and the line x=3.
Find the area of the region R

the curve starts at (1,0)
area = [integral] (x+1)^(1/2) dx from 1 to 3
= (2/3)(x+1)^(3/2) from 1 to 3
= (2/3)(4)^(3/2)
= 16/3
check my arithmetic
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