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Could you show me step by step how to find the inverse of this problem: log with base of 2 (x+1) Thanks! It is not clear what the problem is. You are given a function of x. Let's calli it y. Are you trying to come up with an equation … 
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Find the inverse of f(x) = log(2+x)  4 the base is "a" Call f(x) y y = loga(2+x) 4 y+4 = loga(2+x) a^(y+4) = 2 + x x = a^(y+4)  2 drwls, you have merely solved the equation for x. The question was to find the "inverse", so the actual … 
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1 (a) A function passes through the points (0, 5), (1, 0), (2, 7). Use finite differences to determine the equation of the function. (b) Draw the graph of the function. (c) Draw the inverse on the graph. (d) Show at least two different … 
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How do I start to solve 2log8(x+1) = 8? 
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How do you find the inverse of functions? 
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solve: log8(w6)=2log8(w+15) note: the 8 is to be little at the bottom right corner of log 
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h(x) = log (6x+5/7x4) Find a formula for the inverse function h^1(x) h^1(x) = My work so far h(x) = log(6x+5/7x4) y=log(6x+5/7x4) x=log(6y+5/7y4) 7xy4x= log(6y+5) how would I solve from here. Would I solve for y then do the … 
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Solve the equation : 8^2x1 = 16^x+1 i know you have to log both sides log8^2x1 = log16^x+1 and then you use the exponential rule 2x1 log8 = x+1 log16 but then i don't know what to do... 
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1. Solve: log (y1) = log(y9) 2. Find the inverse of the logarithmic function f defined by f(y)= 2log5 (2y8)+3.