math
posted by kozy .
Given the quadratic function f(x) = 16x2 – 64x + 64, find a value of x such that f(x) = 16.

f(x) = 16x2 – 64x + 64
for f(x)=16, write:
16=16x²  64x +64
transpose 16 to the right, and factor out numeric factor 16:
16(x² 4x +3) = 0
Factor expression
16(x3)(x1)=0
This means that x=3 or x=1, either one of which satisfies the equation
f(x)=16.
Check by substituting x=3 or x=1 in f(x).