posted by Anonymous .
Find the exponential function of the form y=ax^b whose graph passes through the points (-3, 1/27) and (0,1).
I don't know where to begin with this problem??
(0,1) means when x=0, y=1.
y = a*0^b = 0 except when b=0, when y is undefined.
So y cannot equal 1 when x=0.
Please check if there is a typo, for example: y=ab^x instead.
If this is the case, then
1/27 = b^(-3)
27 = b^3;
So what do i put as the answer? is 3 the esponential function then?
"Please check if there is a typo,..."
When you see what the question actually asks, then you can decide which way to go.
Especially in exams, you need to double-check what you've copied the question correctly before you start.
Im sorry yes there was a typo, you correctly fixed it. the b should be an x so it should look like this.
So the second solution would be appropriate. BUT... do make sure you understand how the solution was obtained, promise?
I do! thank you so much!!