chemistry

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what is the molarity of a solution containing 23g of NaCl in 500 mL of solution? (the molecular mass of NaCl is 58.44.)

  • chemistry -

    molarity = moles solute / L solution

    Convert g to moles:

    23g NaCL x 1 mol/58.44 g NacL = 0.394 mol

    Convert ML to Liter:

    500 mL x 1 L /1000 mL = 0.5 L

    Therefore...

    M= 0.394 mol/0.5L = 0.788 Molarity.. should be the right answer

  • !@#$%^& -

    no way

  • chemistry -

    No of moles = mass / molar mass
    = 5.85/58.5
    = 0.1 miles

    Molarity = no of moles / volume
    = 0.1/500 ×1000
    = 0.2 M ANSWER

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