# chemistry

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what is the molarity of a solution containing 23g of NaCl in 500 mL of solution? (the molecular mass of NaCl is 58.44.)

• chemistry -

molarity = moles solute / L solution

Convert g to moles:

23g NaCL x 1 mol/58.44 g NacL = 0.394 mol

Convert ML to Liter:

500 mL x 1 L /1000 mL = 0.5 L

Therefore...

M= 0.394 mol/0.5L = 0.788 Molarity.. should be the right answer

• !@#\$%^& -

no way

• chemistry -

No of moles = mass / molar mass
= 5.85/58.5
= 0.1 miles

Molarity = no of moles / volume
= 0.1/500 ×1000

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