PreAlgebra
posted by Shelbie .
My tens and units digits are consecutive integers whose product is 2/3 of my hundreds digit.
My units digit is 1/3 of my hundreds digit.
The sum of my digits id equal to the sum of the first five counting numbers.
What year am I?

2 * 3 = 6 = (2/3) 9
Assuming the year has a thousands digit, it must be 1 to sum to 15 = 1 + 2 + 3 + 4 + 5.
1923
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