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What are the oxidation numbers for the elements in the compound C2H5COOH?

  • chemistry -

    I do these this way.
    First, I keep H and O "normal" if I can and let C change to whatever I need.
    The formula becomes C3H6O2
    H = +1 each x 6 = +6
    O = -2 each x 2 = -4
    Which means C must be -2 for three of them or -2/3 each to make the compound zero (and all compounds are zero).
    Here is a very good link.

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