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The width of a rectangle is three fourths of the length. The perimeter of the rectangle becomes 50 cm when the length and the width are each increased by 2 cm. Find the length and the width.

  • math -

    original length --- x
    original width ---- 3x/4

    new length = x+2
    new width = 3x/4 + 2

    2(x+2) + 2(3x/4 + 2) = 50
    x + 2 + 3x/4 + 2 = 25
    times 4

    4x + 8 + 3x + 8 = 100
    7x = 84
    x = 12

    length was 12
    width was 9

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