math
posted by risha .
The width of a rectangle is three fourths of the length. The perimeter of the rectangle becomes 50 cm when the length and the width are each increased by 2 cm. Find the length and the width.

original length  x
original width  3x/4
new length = x+2
new width = 3x/4 + 2
2(x+2) + 2(3x/4 + 2) = 50
x + 2 + 3x/4 + 2 = 25
times 4
4x + 8 + 3x + 8 = 100
7x = 84
x = 12
length was 12
width was 9
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