Grade 11 Math
posted by Stacy .
A rectangular dog run is to be enclosed by a fence and then divided into two smaller rectangular areas by a fence parallel to one of the sides. If 54m of fence is available, find the dimensions of the dog run of greatest possible area. State the total area

Grade 11 Math 
MathMate
Let x be the shorter side.
Longer side = (543x)/2 = 271.5x
Area, A = x(271.5x)=27x1.5x²
To get maximum area, diff. w.r.t. x and equate to zero.
dA/dx = 273x=0
x=9m
longer side = 279*1.5=13.5m
The dog run is 9m by 13.5 m total
Total area= 121.5 m²
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