College Algebra

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A coin jar contains nickels, dimes and quarters. There are 46 coins in all. There are 11 more nickels than quarters. The value of the dimes is $1.00 less than the value of the quarters. How many coins of each type are in the jar?

  • College Algebra -

    Solve the system:
    n+d+q=46
    n=q+11
    10d=25q-100
    From the 3rd -->d=2.5q-10
    The 1st: (q+11)+(2.5q-10)+q=46

    q=10
    n=21
    d=15

  • College Algebra -

    solving using the elimination method and identify the system as consistent, inconsistent or dependent.
    3x-4y=8
    6x-2y=10

  • College Algebra -

    Suppose that Maria has 120 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 14 less than twice the number of pennies; the number of dimes she has is 22 less than three times the number of pennies. How many coins of each kind does she have?

  • College Algebra -

    p+n+d=120

    n=2p-14

    d=3p-22

    p+(2p-14)+(3p-22)=120

    6p-36=120
    6p=156
    p=26

    n=2(26)-14
    n=52-14
    n=38

    d=3(26)-22
    d=78-22
    d=56

  • College Algebra -

    P(1, 2); Q(8, 26)

  • College Algebra -

    5+6

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