posted by Deanna .
The total pressure in a flask containing air and ethanol at 25.7C is 878 mm Hg. The pressure of
the air in the flask at 25.7C is 762 mm Hg. If the flask is immersed in a water bath at 38.8C, the
total pressure is 980 mm Hg. The vapor pressure of ethanol at the new temperature is mm Hg.
I got it P1/T1=P2/T2 will get you there
initial pressure of the air(P1) = 762mm Hg
P2 = ?
T1 = 25.7+273 = 298.7K
T2 = 38.8+273 = 311.8K
P2 = 762 mm Hg x 311.8K/298.7K = 795.42 mm Hg
so, pressure of ethanol = 980 - 795.42 = 184.58 mm Hg
Answer in three sig fig will be 184 mm Hg.