A professor knows that in her class 37% of the students have passed an Algebra course, 29% have passed an English course, and 21% have passed both courses. If one student is selected at random from this class, find the probability that:
c) the student did not pass algebra.
To find the probability that the student did not pass algebra, we need to subtract the probability of passing algebra from 1.
First, let's find the probability of passing algebra:
Given that 37% of the students passed algebra, the probability of passing algebra is 37% or 0.37.
Next, subtracting the probability of passing algebra from 1 gives us the probability of not passing algebra:
Probability of not passing algebra = 1 - Probability of passing algebra
Probability of not passing algebra = 1 - 0.37 = 0.63
Therefore, the probability that the student did not pass algebra is 0.63 or 63%.
To find the probability that the student did not pass algebra, we need to subtract the probability that the student did pass algebra (37%) from 100%.
Step 1: Calculate the probability that the student did pass algebra.
P(passed algebra) = 37%
Step 2: Calculate the probability that the student did not pass algebra.
P(did not pass algebra) = 100% - P(passed algebra)
P(did not pass algebra) = 100% - 37%
P(did not pass algebra) = 63%
Therefore, the probability that the student did not pass algebra is 63%.