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The area of trapezoid is h( b1+b2)/5,where h is the altitude, and b1 and b2 are the lenghts of the parallel bases. If trapezoid has an altitude of 5 inches, an area of 55 square inches , and one base 12 inches long, what is the length, in inches, of its other base?

  • math -

    A = h( b1+b2)/2
    not over 5 I think

    No need to think. Just write the equation down and plug in the numbers:

    55 = 5 (12+b2)/2
    22 = 12+b2
    b2 = 10

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