Search: The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.029 kg and is moving along the x axis with a velocity of +5.5 m/s. It makes a collision with puck B, which has a mass of 0.049 kg and is initially at rest. After the collision, the two pucks fly apart with the angles shown in the drawing.
To find the solution, we need to use the principles of conservation of momentum and conservation of kinetic energy.
1. Conservation of momentum:
The total momentum before the collision is equal to the total momentum after the collision. Mathematically, we can represent this as:
(mass of puck A * velocity of puck A) + (mass of puck B * velocity of puck B) = (mass of puck A * velocity of puck A') + (mass of puck B * velocity of puck B')
Here, puck A is moving along the x-axis with a velocity of +5.5 m/s, and puck B is initially at rest. Puck A' and puck B' represent their velocities after the collision.
2. Conservation of kinetic energy:
The total kinetic energy before the collision is equal to the total kinetic energy after the collision. Mathematically, we can represent this as:
0.5 * mass of puck A * (velocity of puck A)^2 + 0.5 * mass of puck B * (velocity of puck B)^2 = 0.5 * mass of puck A * (velocity of puck A')^2 + 0.5 * mass of puck B * (velocity of puck B')^2
Once we solve these two equations simultaneously, we can find the velocities of both pucks after the collision.
Note: The drawing mentioned in the question is missing, so we cannot provide specific angles or velocities. However, the above explanation provides the general approach to solve the problem.