# Calc 2

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Find a Cartesian equation for the polar curve y = 5tan(theta)sec(theta). I think I got it but I just wanted to double check. Thanks in advance!

• Calc 2 -

Would you like to post your answer if you just wanted to check?

• Calc 2 -

y=... or r=...?

• Calc 2 -

It would be in the form:
x=f(θ),
y=g(θ)
where f and g are functions of θ.

• Calc 2 -

• Calc 2 -

If r=tan(theta)sec(theta)
then r(cos(theta)^2)=sin(theta)
(r*cos(theta))^2=r*sin(theta)
x^2 = y

• Calc 2 -

I am sorry, it is r = 5tan(theta)sec(theta)

• Calc 2 -

Mggraph: but (r*cos(theta))^2 is not x^2, is it? I thought rcos(theta) = x^2

This is what I got:

1 = 5y/[(x^2)(square root of(x^2 + y^2))]

• Calc 2 -

Then all right sides multiply by 5:
x^2=5y or
y=0.2x^2

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Aha I got it! Thanks so much! :)

• Calc 2 -

if I've this equation: r=sec theta tan theta. How is?

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