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An unknown was prepared with the concentration of 0.000630 M. A Beer's Law plot was prepared using the absorbance values from standard solutions of ASA and a line drawn through all the points passed through the origin with a slope of 1550.2 M–1 . The expected absorbance and %T values for the diluted aspirin solution prepared by the student is _______ and _________, respectively.

  • chemistry -

    If you plot these as A vs C, and if it obeys Beer's Law, it gives a straight line passing through the origin with the slope of Absorbance/concn = 1550.2.
    Thus A = 1550.2*0.000630 = ??
    and A = log(100/%T)

  • chemistry -

    0.98 is correct
    but the second part is not right

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