# chemistry

posted by .

For a solution that is 0.280M HC3H5O2 (propionic acid, Ka= 1.3*10^-5) and 0.0894M HI , calculate the following:

[H3O+]
[OH-]
[C3H5O2-]
[I-]

• chemistry -

You should write out the equations to understand what is going on. Let's call propionic acid HP.
.............HP ==> H+ + P-
initial.....0.280M...0....0
change......-x.......x.....x
equil.....0.280-x....x......x

...........HI ==> H+ + I-
initial..0.0894....0....0
equil.......0..0.0894..0.0894

Ka = (H+)(P-)/(HP)
Substitute from the ICE charts and solve for (P-). (H+) = 0.0894+x and (HP) = 0.280-x

## Similar Questions

1. ### Chemistry, #5

For propanioic acid, HC3H5O2, Ka=1.3 x 10^-5, determine the concentration of the species present, the pH and the percent dissociation of a 0.21 M solution. Do this for H+, OH-, C3H5O2-, HC3H5O2, and the pH and percent dissociation. …
2. ### chemistry

Consider the Ka values for the following acids: Cyanic acid, HOCN, 3.5 ´ 10-4 Formic acid, HCHO2, 1.7 ´ 10-4 Lactic acid, HC3H5O3, 1.3 ´ 10-4 Propionic acid, HC3H5O2, 1.3 ´ 10-5 Benzoic acid, HC7H5O2, 6.3 ´ 10-5 Which of the following …
3. ### Chemistry

Calculate the pH of a solution that is 0.060 M in potassium propionate(C2H5COOK or KC3H5O2) and 0.085 M in propionic acid (C2H5COOH or HC3H5O2)
4. ### ap chemistry

For propanoic acid (HC3H5O2, Ka = 1.3 10-5), determine the concentration of all species present, the pH, and the percent dissociation of a 0.29 M solution. [H+] [C3H5O2-] [OH -] [HC3H5O2] pH percent dissociation
5. ### Chem

For a solution that is 0.280 M HC3H5O2 (propanoic acid Ka=1.3*10^-5) and 0.0894 M HI, calculate the following. Concentration of H30, OH, C3H5O2-, I-
6. ### chemistry

1. if 15.0mL of 4.5 M NaOH are diluted with water to a volume of 500mL, what is the molarity of the resulting solution?
7. ### Chemistry

What must be the molarity of an acetic acid solution if it has the same percent ionization as 0.150M HC3H5O2 propionic acid,Ka=1.3*10^-5 )?
8. ### Chemistry

What is the pH of a solution that is .060M in potassium propionic and .085M in propionic acid?
9. ### General Chemistry

Calculate the pH and include the balanced equation for the acid dissociation reaction. 0.20 M HC3H5O2 (propionic acid, Ka = 1.3 x 10^-5)
10. ### Cara-Chem

I made a bobo, which may lead to some confusion. Here is my post revised: You don't need it. Just calculate the new molarity of the acid after addition of NaOH, and then determine the molarity of the acid in solution. How many moles …

More Similar Questions